Monday, 20 June 2016

SSC Hack Book Launched !

It gives me great pleasure to announce the publishing of "SSC Hack-book"
All the hacks in a single ebook!





Taking feed-backs from many candidates, I decided to compile all the tricks in a single document for your convenience. "SSC Hack Book" contains all the hacks that have been discussed in this blog plus some additional solved examples. Moreover, I have also covered some major topics of English - Active Passive Voice, Direct-Indirect Speech, Para-Jumble and Grammar Rules.

You can check the contents of the book below-

Contents




For those of you who are new to the blog and are skeptical, check-out the first chapter of the book -
Chapter-1 (Algebra Hacks)

Since this book is a result of some original work, a price-tag was inevitable.
But I have kept it to a bare minimum, i.e. Rs 69/- equivalent to a paneer roll :)
Click on the below link to purchase your copy-


[The book is in PDF format. You will have to read it in your laptop/mobile]



[You will receive your eBook on the email ID that you will provide in the form]

If you are not able to buy this book for any reason, drop a mail at:
prashantrajcalling@gmail.com
Subject: Not able to buy SSC Hack Book
In the mail, explain the problem and I will give you an alternate way to buy.

And yes, this eBook doesn't mean that I will stop writing on this blog. The free content will continue to flow...

Like the "SSC Hacks" official facebook page to receive timely updates about the new hacks/tricks.
https://www.facebook.com/sschacks.official/


EDIT-

Thank you guys for the amazing response you have given to my book. It's been one week since the launch, and the sales have already crossed the 500 mark. I promise you this book would prove to be more helpful than all the other CGL books that you purchase.

Thanks again and keep rocking!!! :)


Update (June, 2017): Many people are asking me if the buy link is still working or not. I would like to clarify that the link is very much operational and you can go ahead with the purchase.



Friday, 10 June 2016

Life as an Assistant in MEA

Like the "SSC Hacks" official facebook page to receive timely updates about the new hacks/tricks.
https://www.facebook.com/sschacks.official/



ASO (Assistant Section Officer) in MEA is one of the best posts offered by CGL. There is a lack of genuine information about MEA and I am here to provide some first hand experience to you.

Many candidates enquired about the job profile, work-life balanace, foreign postings, etc. and this post covers them all. Consider it a motivational post for all the MEA aspirants :)

1. Joining - First things first, MEA is very notorious for offering late joining because it has some additional verifications like IB verification, BOS clearance, etc. But things have changed now. Recently DoPT came up with a circular which instructed all the ministries to give joining to all the selected candidates even if their police verification is not done. Now they will just make you sign a undertaking stating that your conduct has been flawless throughout your career. Result? Faster joining. You can expect to get your joining letters within three months of declaration of the result. Something to cheer about :)

2. Work Environment - THE BEST!!! without doubt. Most of the Assistants (not all) get to sit in Jawaharlal Nehru Bhawan (JNB), a newly constructed building at the heart of the city with all the latest amenities.

The entrance:



Greenery all around:-


Come to the terrace for a cup of coffee


3. Work desk:

My colleague, busy at work-


3. Promotions:

You join as Assistant Section Officer. After clearing departmental exam, you will get your first promotion as Section Officer (this will take 4-5 years), and you will get to sit on this-

Around 4-5 ASOs work under a Section Officer.
The second promotion will change your grade pay but the designation will remain the same. Your third promotion will make you Under Secretary(US) and you will get your own room. (this takes around 15 years minimum). After US, the hierarchy is Deputy Secretary -> Director (Dir)-> Joint Secretary, JS (the farthest an ASO can go)

4. Type of work:

All the assistants appointed through CGL(whether CSS or MEA) do the same work. i.e. making a Note and an Order. The type of the Note, depends on the section in which you work. All the sections have different work - a Section to manage the travel of diplomats, another Section to process the medical bills, etc. of the employees, Section to communicate with the Embassies, etc.
Consider for e.g. you have to process a loan application of an employee (All central government employees have to take prior permission of the government before raising any loan from a bank). The employee will give you an application mentioning his basic salary, date of joining, date of retirement, purpose of loan, etc. and you have to make a note out of it. In the note, you will state that employee X wishes to raise a loan from ABC bank. Then you will calculate the repaying capacity of the employee with a predefined formula. The employee cannot get a loan beyond his repaying capacity.
All the notes follow different paths - like for a loan, the note moves from SO->US->Dir-> and finally JS. Once the JS signs it, the note returns to you. If the above people haven't raised any objection, you will go on making an Order. Your SO will sign it and move forward. Once an order is issued, the employee can raise the loan.
This is the gist of your work.

5. Work-Life Balance:
It depends on the section in which you work. Mostly you have to work from 9:00 a.m. to 05:30 p.m, with one hour for lunch-break and 1 hour for tea-breaks (30 minutes, twice), although you can extend them if you want.

6. Subsidised food:
JNB has appointed Bikano as its caterer. The food is cheap and tasty. Most of the people eat thali, which costs them Rs. 60/-. Each floor has a coffee/tea vending machine, but you would have to shell out Rs. 5 for coffee and Rs 6 for tea.


7. The MEA edge:

Now the things that you wont find in other SSC posts-

7(i) MEA Quota(Welfare) in top colleges of India-
The MEA officials, when posted abroad, can avail MEA quota to enrol their children in top government colleges of our country (top NITs, NSIT, DTU, etc.). Your children can apply through this quota and can get a seat in these coveted colleges circumventing the formidable JEE exam (they will have to appear for SAT though). The competition through this quota is almost non-existent.

7(ii) Best work place
Population density at JNB is quite low. The whole building looks empty and there is no rush to get a lift or to eat at cafeteria, etc. The work place of most of the other ministries is crowded and doesn't give you that feeling of 'uniqueness'.

7(iii) MEA Quarters
Among all the SSC posts, MEA is the first one to offer you a government accommodation. You will get a 2-BHK flat in Dwarka after around 1.5 years of your joining. In CSS, you won't get government quarter even after 10 years of service.

7(iv) Temporary Deputations (TDs)
All over the internet you would find that MEA assistants spend 3 years in India and 3 years abroad. But there is more to that. MEA Assistants also go on Temporary Deputations (if you work in Protocol Division) for important international summits like SAARC, BRICS, India-Africa Forum Summit, etc.

7(v) Foreign Postings
ASOs generally get foreign postings for 3 years straight, but no one would force you to go. In some Sections you can avoid foreign postings altogether.
Most of the MEA officials are ready (and eager) for foreign postings, and the reason is simple - A hell of a lot of money! (besides the thrill of travelling)

Your allowances mostly depend on the country but they are always more than you need.
For poorer countries like Bhutan and Bangladesh
For a country like Bangladesh, you will get $2,200/month + Your basic salary in India (which after 7th pay commission would be around Rs. 45000). Total = Around 1,92,000/month. Now, you already get free government accommodation, so your biggest expense is already taken care of; you just have to spend on food and shopping. In a country like Bangladesh, even if you live a lavish lifestyle, your expenses wont cross 20,000/month
Savings = Rs. 1,92,000 -  Rs. 20,000 = Rs. 1,72,000/month

For rich countries
Your savings are almost same in all the countries. If you are posted in USA/UK/Japan, you will get around $2,700/month plus your Basic salary in India.
Earnings = 2,25,000/month
Savings = Your expenses won't exceed Rs. 50,000/month (my friend posted in Tokyo has never spent more than Rs. 40,000 in a month).
Savings = Rs. 2,25,000 - Rs. 50,000 =  Rs. 1,75,000/month
Even after adding some invisible costs over your extravagant lifestyle, minimum Rs. 1.5 lakhs/month are definitely going into your pocket.

You would be surprised to know that the places like Nepal, Bhutan, Pakistan, Bangladesh,etc. are more desirable than UK, USA, Italy, etc. because these places are near your home, hence reducing your travel expenses drastically. (MEA only pays for one visit per year)

That's all :)  I think I have covered all the doubts, but still if you have any queries about this job, feel free to drop a comment...


To buy the super-hit SSC Hack book, follow the below link-
Buy SSC-Hack Book


Monday, 6 June 2016

[Q] Geometry Tricks - 3 [Construction]

You can tackle many tricky geometry questions with a single word 'Construction'. Yes, just precisely draw the diagram as asked in the question and manually measure the unknown side/angle that has been asked...

Disclaimer: Use this method only when you are unable to figure out how to solve a question.

Q. 1) If BE and CF are two medians of a triangle ABC and G is the centroid and EF and AG intersects each other at O then find - AO:OG
(A) 1:1             (B) 1:2              (C) 2:1                (D) 3:1

Since no information about the type of triangle is given, hence we will assume it to be 'Equilateral'.
Step 1: Draw an Equilateral triangle of any size(but it should be big enough for the purpose). Take 6 cm.
How to draw an equilateral triangle? Just draw a line AB = 6 cm, and make ∠A = 60 and ∠B = 60, the point where the two angles will intersect, will be point C.
Step 2: Now draw the medians BE and CF. Make sure that E and F lie exactly in the middle of AC and AB respectively.
Step 3: Complete the remaining figure.
Step 4: Measure AO and OG with a ruler.


You will find that AO:OG = 3:1
Answer: (D)


Q. 2)


Again, a simple question.
Step 1: Draw a circle of any radius with centre O and diameter AB.
Step 2: Put protractor at A and draw ∠CAB = 34.
Step 3: Join BC
Step 4: Measure ∠CBA with protractor.
Answer: (C)



Q. 3)

This may appear tricky if you go on solving it with conventional methods. But it is way too easy when solved through construction.
Step 1: Draw a triangle ABC with AC = 6 cm. Here we are using the concept of scaling. In the exam you can't draw a line 12 cm long. Hence we are reducing AC to 1/2. Hence, when we will measure AE, we will have to multiply it by 2 to get the exact answer.
Step 2: Draw internal bisector of ∠ABC. Now, be very cautious, a slight mis-measurement give you a wrong answer. Use protractor for accurate measurements (For simplicity, you can take ∠A = 60 and hence use protractor to make ∠CBD = 30)
Step 3: Again with the help protractor, make ∠BDA = 90
Step 4: Draw DE parallel to BC
Step 5: Measure AE with a scale. You will get AE = 3 cm.
Hence actual length of AE = 2*3 = 6 cm
Answer: (B)
Method:

AD extended meets BC at F. 
∠ADB = ∠BDF = 90
∠ADB = ∠FDB (BD is the angle bisector)
∠BAD = ∠BFD
Triangles ABD and FBD are congruent. So AD = DF
Triangles ADE and AFC are similar
AE/AC = AD/AF = 1/2
AE = 1/2 * 12 = 6 cm



Q. 4) 





Although this is a very simple question and you would get 60 degrees as your answer when you solve it. But, if by any chance, if you are not able to figure out the method, solve it using construction.
Method: The median of an isosceles triangle cuts the opposite side at right angles. Hence ∠AOB = 90.




Similarly you can solve many geometry questions with proper measurements. Try solving some questions on your own...



Sunday, 29 May 2016

[Q] Mensuration Tricks - 2


This is a famous question. Just remember whenever you are forming a circle and then a square,
the side of that square is given by, a = 1.6*r (approx.), where r = radius of the circle
I have written approx. because the actual formula is 1.57*r, but it will make the calculations a bit lengthy. So, just find 1.6*r and the answer will be little less than that. Like here
Side = 1.6*84 = 134.4, so the answer is 132 cm
Answer: (A)

When the wire is bent in the form of a circle of radius 84cm, that means the circumference (or the length of the wire) of the circle is 2*Ï€*84 = 44*12 cm
Now this wire forms a square of (let’s say) side ‘a’
Then, 4a (perimeter of the square) = 44*12
Hence a = 132 cm




If the given rectangular sheet of paper (length =l, breadth = b) is rolled across its length to form a cylinder, having a height b, then volume of cylinder = (l*l*b)/4Ï€
If rolled across its breadth, then = (b*b*l)/4Ï€
In this question the sheet is rolled along its length, so volume = (l*l*b)/4π = 12*12*5/(4* π)
Volume = 180/ π cm3
Answer: (C)

In this question, the ratio of surface areas is given and they are asking the ratio of volumes. The word “sphere” is useless here. In such questions, just imagine area as A2 and volume as A3. Now A3 is given and you have to find A3. How will you do it? Simple, first take the square-root of A2 to convert it into A, and then take the cube of A to find A3.

So for solving this question, we just have to take the square-root of 4:9. The ratio will become 2:3. Then take the cube of 2:3. Hence the answer is 8:27
Answer: (C)


Here again ratio of areas is given, that means A2 is given, and we have to find A. So 4:9 will become 2:3
Answer: (A)


Diameter and perimeter are directly proportional, P = D*Ï€, where P is the perimeter and D is the diameter.
Hence a 75% increase in diameter means a 75% increase in perimeter
 Answer: (D)


The area of base and the volume of a cone are directly proportional V = A * h/3, where V = volume and h = height of the cone
Hence a 100% increase in the area of the base would mean a 100% increase in the volume
Answer: (B)

A is increased by 50% hence A2 (or surface area) will increase by (1.5*1.5 – 1)*100 % = 125%
Note: Similarly A3 (or volume) will increase by (1.5*1.5*1.5 – 1)*100 % = 237.5%

Answer: (A)

Where ever the word “melting” is used in mensuration, it means only one thing – equate the volume
The volume of the rectangular block = l*b*h = 21*77*24 cm3
Now this volume will be equal to the volume of the sphere formed after melting the block
Volume of sphere = (4/3) * π * r3 = 21*77*24
Hence, r = 21 cm
Answer: (A)


The water rises by 5.6 cm. Take this 5.6 cm as the height of the cylindrical beaker and find its volume.
Volume of a cylinder = π*r*r*h = π * (7/2) * (7/2) * 5.6
Volume of the marbles (spherical in shape) = (4/3) * π * r3 = (4/3) * π * 0.7 * 0.7 * 0.7
No. of marbles dropped = Volume of beaker/Volume of a marble = 150
Answer: (B)


Let the radius of the big sphere be R.
Volume of a cone = (1/3) * π * R3 (since radius and volume are same as the radius of the sphere)
Let the radius of the smaller sphere = r
Then volume of cone = volume of smaller sphere
(1/3) * π * R3 = (4/3) * π * r3
r : R = 1 : 22/3
Surface area of smaller sphere(s) = 4 * π * r2
Surface area of larger sphere(S) = 4 * π * R2
S/s = (r/R)2 = 1 : 24/3
Answer: (D)



When a cone is hollowed out from a cylinder, we get the above figure
The whole surface area of the remaining solid = Area of A + Area of B + Area of C
A = curved surface area of the cone
B = curved surface area of the cylinder
C = area of the cylindrical base
A = Ï€ * r * l, where l = slant height of the cone, which is  or
Hence A = π*3*5 = 15π
B = 2Ï€rh = 2Ï€*3*4 = 24Ï€
C = πr2 = π*32 = 9π
The whole surface area of the remaining solid = 15Ï€ + 24Ï€ + 9Ï€ = 48Ï€
Answer: (C)





Given, AB = 3 cm, BC = 6 cm and OF = 1 cm
Height of the cone (AC) = √(6^2 - 3^2 ) = 3√3 cm
Triangles ABC and CFO are similar (RHS similarity)
So, OC/BC = OF/AB
OC = 2 cm, therefore CG = 3 cm (OG = 1 cm)
Now, ABC and CEG are similar
GE/AB = CG/AC
So, GE =
Required volume = Volume of cone (CDE) - Volume of Sphere
                                = 3Ï€ – (4/3)Ï€
                                = (5/3)Ï€

Answer: (C)


If you have any doubt in this article, please drop a comment.
Keep reading :)


Sunday, 22 May 2016

[Banking] Machine Input-Output

Machine input-output is a very important topic for banking exams. I will tell you a short-cut that would help you in solving such questions in a single line, instead of writing all the steps.

Q. 1)

Input: mix  12   in   form   35  are  20   with  47  given
Step I: 47   mix  12   in  form   35   20  with   given   are
Step II: 47   35  mix  12   in   20   with  given   are  form
Step III: 47   35   20  mix  12   in  with   are   form  given
Step IV: 47  35  20  12  mix  with  are  form  given  in
Step V: 47  35  20  12  with  are  form  given  in  mix
Step VI: 47  35  20  12  are  form  given  in  mix  with

As per the rules given above, solve the below input

Input: when  11  given  fine  37  provide  zero  90  over  45  is  29  team  89

Solution: 
First try to find the pattern.
In the given question, each step moves the biggest number to the left and the smallest word to the right. So ultimately are the numbers are sorted in the descending order on the left and all the words are sorted in the ascending order on the right.

Once you have deciphered the pattern, write down the input

Input: when  11  given  fine  37  provide  zero  90  over  45  is  29  team  89

Now in the 1st step the biggest number, i.e., "90" will move to the left, while the smallest number, i.e., "fine" will move to the right. Hence strike-through the words "fine" and "90" and write "1R" and "1L" above them, respectively. Like this:

1R means in the 1st step, "fine" will move to the extreme right and 1L means in the first step, "90" will move to the extreme left.
Now, "89" is the next biggest number and "given" is the next smallest word. Hence, strike-through them and write "2L" and "2R" above them, respectively.


Similarly strike-through the rest of the words.
Your input will look something like this-


That's it, you can now solve all the questions, just by looking at the above figure.

Q. 1(a) Which number/word would come on the fourth position(from the left) in step II ?

From our figure we can see that in the 2nd step, the words having the code "1L" and "2L" will move  to the left and the words having the code "1R" and "2R" will move to the right. All the other words/numbers won't change their positions. Hence, step II will look like this: (I am writing the whole step just for the sake of explanation. You can easily imagine the step in your head)

Step II: 90  89  when  11  37  provide  zero  over  45  is  29  team  89  fine  given

So the fourth word from the left is "11"

Q. 1(b) How many step would be needed to complete the arrangement?

The farthest our code reached was 8R. Hence the total number of steps is 8.

Q. 1(c) In step IV, which word would be 8th from the left?

In step IV - 1R, 2R, 3R and 4R would be on the right, while 1L, 2L, 3L and 4L would be on the left. Rest of the words/numbers would remain unchanged.

Step IV: 90  89  45  37  when  11  provide  zero  29  team  fine  given  is  over

So the 8th word from the left is "zero".

Short-cut: You have to count from the left. so just look at the image and imagine 1L, 2L, 3L and 4L on the left and count the leftover words (ignoring 1R, 2R, 3R and 4R because they would be on the extreme right).
5th word = when
6th word = eleven
7th word = provide
8th word = zero

Q. 1(d) Which step number would be the following output?

90  89  45  when  11  37  provide  zero  over  29  team  fine  given  is

You can see that three numbers have been arranged on the left and three numbers have been arranged on the right. So it is the 3rd step.

Let us take another question

Q. 2) Input: gone name 43 39 18 for again 66

Step 1 : 66 gone name 43 39 18 for again
Step 2 : 66 again gone name 43 39 18 for
Step 3 : 66 again 43 gone name 39 18 for
Step 4 : 66 again 43 for gone name 39 18
Step 5 : 66 again 43 for 39 gone name 18
Step 6 : 66 again 43 for 39 gone 18 name

Based on the above rule, sort the below input-
Input: their 19 27 dent are 91 hour zero 31 16 chairs

The pattern is simple: Numbers and words are arranged alternatively, with numbers following descending order and words following ascending order.

After sorting, the input will look like this:


Note few things:
  1. I have only written 1L, 2L, etc. and no "R" because the words/numbers are only moving to the left. 1L means in the first step the word coded "1L" will move to the left and "2L" means in the second step, the word coded "2L" will move to the second position from the left.
  2. I have not numbered "their" and "zero" because after striking-through 16 (i.e. 9L), you will notice that the words "their" and "zero" are already sorted in the ascending order. So no need to  write 10L over "their" and 11L over "zero". Had the situation been something like this-
          Then you would have written "10L" over "their" and 11L over "zero".


Q. 2(a) Which of the following will be step 4 ?

A.) 91 are 31 their 19 27 dent hour zero 16 chairs
B.) 91 their 19 27 dent are hour zero 31 16 chairs
C.) 91 are 31 chairs their 19 27 dent hour zero 16
D.) 91 are 31 chairs 27 dent 19 their hour zero 16


Look at the solution figure: 

In the fourth step- 1L, 2L, 3L and 4L will move to the left and rest of the words/numbers will remain as it is. So the fourth step will look like this:
91 are 31 chairs their 19 27 dent hour zero 16

Answer: (C)

Q. 2(b) How many steps would be needed to sort the input?

Answer: 9 (because the highest numbering is 9L)


Q. 2(c) Which of the following would be final arrangement ?

A) 91 are their 27 19 dent hour zero 31 16 chairs
B) 91 are 31 chairs 27 dent 19 hour 16 their zero
C) 91 are 31 chairs 27 19 dent hour 16 their zero
D) 91 are 31 chairs 27 dent 19 zero hour 16 their

It's easy. Sort the numbers and words alternatively with numbers following descending order and words following ascending order.
Answer: (B)


I think by now you must have understood this method. Solve some questions to get a hold of it.
If you have any doubt in this article, please drop a comment.
Keep reading :)

Sunday, 15 May 2016

[Banking] Coded Inequality

Almost all of you are appearing for Banking exams along side SSC, so I decided to write few important articles on it. This post deals with "Coded-Inequality".

Q. (1) Statement: F < B ≥ A = C > D
          Conclusion: (1) B ≥ C              (2) F > C

You have to find whether the conclusions (1) and (2) are true or false.
How to solve such questions quickly? The answer is "Magic Square"


When you get the rough sheet in the examination hall, immediately draw this magic square. Although after solving more and more questions, soon you would be able to memorize it.
Rules of magic square:
  1. Always prefer smaller value:
  2. Simple and (`) do not have any relation
  3. "3" is universal

Now let's move to the question
Conclusion 1 (B ≥ C)
The first conclusion is B ≥ C. We know from the magic square that ≥ evaluates to "2". Now, note the positions of B and C in the statement and solve all the signs between them.


Note: There is a typo in the above image. It should be F < B
We know that among two numbers, we choose the smaller one. Hence 2 and 3 evaluate to 2.
The statement as well as the conclusion evaluates to "2". This means that this conclusion is correct.

Conclusion 2 (F > C)
Second conclusion F > C. We know from the magic square that > evaluates to 1. Now, note the positions of F and C in the statement and solve all the signs between them.

You won't be able to solve the statement because the first two symbols do not have a relation between them. So no need to check the rest.
If at any point in the statement you encounter "no relation" between symbols, you can be sure that the conclusion is wrong.

Q. 2)  Statement: F < A = B ≥ C ≤ D
          Conclusion: (1) B > F              (2) A ≥ C

Conclusion 1 (B > F)
Notice that in the statement, the direction is from F to B, but in the conclusion (B > F), the direction is from B to F. Hence to make the directions same, we will write the conclusion as F < B. So it evaluates to 1`.




The statement evaluates to 1` and the conclusion too evaluates to 1`. Hence the conclusion is right.

Conclusion 2 (A ≥ C)
Here the direction is same. So simply, the conclusion evaluates to 2. Now evaluate the statement.
The statement as well as the conclusion evaluates to 2. Hence the conclusion is right.

In the similar manner you can solve all the questions of Coded Inequality quickly. But make sure the question is in the desired format. Notice the below question for instance,

Q.  Statements F % T, T @ J, J # W.
Conclusions 1) J @ F. 2) J # F

Note that:
P is neither smaller than nor equal to Q means P > Q
P is neither greater than nor smaller than Q means P = Q
P is neither greater than nor equal to Q means P < Q
P is not greater than Q means P ≤ Q

First convert the statement in the desired format.
Statement: F ≤ T = J > W
Conclusion: (1) J = F        (2) J > F
Now solve the question with magic square method.


If you have any doubt in this article, please drop a comment.
Keep reading :)

Monday, 9 May 2016

[Q] Averages Tricks - 1

Q. 1) The average weight of 4 men is increased by 3 kg when one of them who weighs 120 kg is replaced by another man. What is the weight of the new man?

Weight of new person = Weight of removed person + No. of persons * Increase in Average = 120+3*4
Weight of new person = 132 kg

Q. 2) The average marks obtained by 120 candidates in a certain examination is 35. If the average marks of passing candidates is 39 and that of the failed candidates is 15, what is the number of candidates who passed the exam?

Such questions are best dealt with allegation formula:
Mean value = 35, Dearer value = 39 and Cheaper = 15
Failed students : Passed students = (Dearer - Mean) : (Mean - Cheaper) = 39 - 35 : 35 - 15 = 4 : 20
No. of students who passed = (5/6) * 120 = 100

Q. 3)

Correct Average = Incorrect average + (Correct value - Incorrect value)/Total observations
Correct Average = 35 + (85 - 45)/20 = 37
Answer: (D)

Q. 4)

Take x = 1
Then A = (1 + 1)/2 = 1
Average of x^3 + 1/x^3 = (1 + 1)/2 = 1
Now put A = 1 in all the four options and check which one is giving '1' as the output
Answer: (D)

Q. 5)


For consecutive numbers:
If the number of terms is odd (e.g. A, B, C), then their average is the middle term(i.e. B).
If the number of terms is even(e.g. A, B, C, D) then their average is (B+C)/2
So here, the average of eight consecutive even numbers = (5th term + 4th term)/2
Given, (5th term + 4th term)/2 = 93
5th term + 4th term = 186
We know, 5th term - 4th term = 2
Adding the equations, we get 5th term = 94
Hence 8th term = 5th term + 2 + 2 + 2 = 100
Answer: (C)


Q. 6)

Average = (8*3 + 20*2 + 26*m + 29*1)/(3 + 2 + m + 1)
17 = (93 + 26m)/(6 + m)
102 + 17m = 93 + 26m
m = 1
Answer: (A)


Q. 7)

Given, (3a + 4b)/2 > 50
3a + 4b > 100
5a > 100  [Since a = 2b]
a > 20
Hence the smallest value of a is 21
Answer: (D)

Q. 8)

Average of six numbers a,b,c,d,e,f = (Average of a,b + Average of c,d + Average of e,f)/3
3.95*3 = 3.4 + 3.85 + x
x = 4.6
Answer: (C)


Q. 9) The average of 11 numbers is 50. The average of first six numbers is 49, and that of last six is 52. Find the sixth result.
This is a common CGL question and a short-cut to solve it is:
Sixth result = 50 + 6{(52 - 50) + (49 - 50)} = 50 + 6(2 - 1) = 56
Answer: 56


Q. 10)

Answer: (B)



Q.11)




If you have any doubt in this article, please drop a comment...
Keep reading :)

To buy the super-hit SSC Hack-Book, follow the below link-
Buy SSC Hack-Book