**Q. 1) The average weight of 4 men is increased by 3 kg when one of them who weighs 120 kg is replaced by another man. What is the weight of the new man?**

Weight of new person = Weight of removed person + No. of persons * Increase in Average = 120+3*4

Weight of new person = 132 kg

**Q. 2) The average marks obtained by 120 candidates in a certain examination is 35. If the average marks of passing candidates is 39 and that of the failed candidates is 15, what is the number of candidates who passed the exam?**

Such questions are best dealt with allegation formula:

Mean value = 35, Dearer value = 39 and Cheaper = 15

Failed students : Passed students = (Dearer - Mean) : (Mean - Cheaper) = 39 - 35 : 35 - 15 = 4 : 20

No. of students who passed = (5/6) * 120 = 100

Correct Average = Incorrect average + (Correct value - Incorrect value)/Total observations

Correct Average = 35 + (85 - 45)/20 = 37

**Answer: (D)**

Take x = 1

Then A = (1 + 1)/2 = 1

Average of x^3 + 1/x^3 = (1 + 1)/2 = 1

Now put A = 1 in all the four options and check which one is giving '1' as the output

**Answer: (D)**

**For consecutive numbers:**

If the number of terms is odd (e.g. A, B, C), then their average is the middle term(i.e. B).

If the number of terms is even(e.g. A, B, C, D) then their average is (B+C)/2

So here, the average of eight consecutive even numbers = (5th term + 4th term)/2

Given, (5th term + 4th term)/2 = 93

5th term + 4th term = 186

We know, 5th term - 4th term = 2

Adding the equations, we get 5th term = 94

Hence 8th term = 5th term + 2 + 2 + 2 = 100

**Answer: (C)**

**Average = (8*3 + 20*2 + 26*m + 29*1)/(3 + 2 + m + 1)**

17 = (93 + 26m)/(6 + m)

102 + 17m = 93 + 26m

m = 1

**Answer: (A)**

Given, (3a + 4b)/2 > 50

3a + 4b > 100

5a > 100 [Since a = 2b]

a > 20

Hence the smallest value of a is 21

**Answer: (D)**

Average of six numbers a,b,c,d,e,f = (Average of a,b + Average of c,d + Average of e,f)/3

3.95*3 = 3.4 + 3.85 + x

x = 4.6

**Answer: (C)**

**Q. 9) The average of 11 numbers is 50. The average of first six numbers is 49, and that of last six is 52. Find the sixth result.**

This is a common CGL question and a short-cut to solve it is:

Sixth result = 50 + 6{(52 - 50) + (49 - 50)} = 50 + 6(2 - 1) = 56

**Answer: 56**

**Q. 10)**

**Answer: (B)**

**Q.11)**

**If you have any doubt in this article, please drop a comment...**

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Thank you sir

ReplyDeleteMost awaited topic .m...

ReplyDeleteThanx a lot

Thanks a lot sir. A question continuously haunting in my mind what will be the safe score to get any post in cgl tier1 + tier 2. Can you share your tier 2 score and how you managed English exam in tier 2. Thanks

ReplyDeleteThanks a lot sir. A question continuously haunting in my mind what will be the safe score to get any post in cgl tier1 + tier 2. Can you share your tier 2 score and how you managed English exam in tier 2. Thanks

ReplyDeleteThanku so much sir...your topics helping a lot ...

ReplyDeleteif 15 men or 24 women or 36 boys can do a piece of work in 12 days, working 8hrs a day, how many men must be associated with 12 women and 6 boys to do another piece of work 6 times as great in 30 days working 6 hrs a day?

ReplyDeleteSir plz help me out in this problem

M1 = 15, H1 = 8, D1 = 12, W1 = 1

ReplyDeleteM2 = X, H2 = 6, D2 = 30, W2 = 6

M1*D1*H1/W1 = M2*D2*H2/W2

X = 48

48 men are required to finish the job

But we already have 12 women and 6 boys

1 woman = 5/8 man

1 boy = 5/12 man

Hence 12 women + 6 boys = 15/2 men + 5/2 men = 10 men

Required no. of men = 48 - 10 = 38

Thanx man for the solution

Deleteprashant...can you suggest any good book that will be enough to cover di part for ssc cgl as well as sbi po !!

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteif pq+qr+rp=0 then find the value of p^2/p^2-qr +q^2/q^2-rp + r^2/r^2-pq

ReplyDeletesir is question ka shortcut bataiye

put p = 2, q = 2 and r = -1

DeleteHello Sir!!....

ReplyDeletepl. tell hw to solve dz ques.??

Q. Ifa+1/b=1 and b+1/c=1 thn value of a.b.c is????

pl. rpl.

This comment has been removed by the author.

Deletea+1/b=1

Delete=>ab=b-1...(1)

b+1/c=1

=>1/c = 1-b

=>c=1/(1-b) ...(2)

Multiply (1) and (2)

abc = (b-1)*1/(1-b)

=>abc = -1

thanks @NHM...

Delete..

[CGL 2014]

ReplyDelete(Please suggest a faster way to solve this)

Q. If x=√5 + 2, then the value

(2x^2-3x-2)/(3x^2-4x-3) is equal to

1. 0.185

2. 0.525

3. 0.625

4. 0.785

I solved this the general way. By Putting the values of x and x^2 in the expression and then calculating it.

This comment has been removed by the author.

ReplyDeleteThnkyou sir

ReplyDeleteSir how to solve

ReplyDeletethis

a+b+c= 1

ab+bc+ca= 2

abc=3 then find the value of

1/(a+bc) +1/(b+ca) +1/(c+ab)

SIR PLZ ALSO POST IN HINDI

ReplyDeleteSIR PLZ ALSO POST IN HINDI

ReplyDeleteSir pls ek post man chldrn women work p bhi bna de ...thnkyou

ReplyDeleteThis comment has been removed by the author.

ReplyDeletein 2nd question..from where 5/6 came?

ReplyDeleteIn that question,last ratio was 4:20 i.e 1:5

Deletefrom there no of passed students=5/5+1=5/6..i hope,now it is clear to you.

hi prashant,

ReplyDeleteIn 2nd question ,from where we got 5/6

Thankyou sir ..

ReplyDeleteSSC CGL-SSC CGL test Pattern 2016 has been released by the SSC and also the candidates ought to check it before going on to prepare for the examination on career chamber portal . career chamber provide full information of SSC CGL 2016.

ReplyDeletesir in 9th question 1 term is common in both first and last 6 terms averages..if that term will not be included..then what will be shortcut??like

ReplyDeleteQ)the average of 25 results is 18.the average of first 12 of them is 14&that of last twelve is 17.find the 13th result..

25*18 - 12*14 - 13*17

Delete25*18 - 12*14 - 13*17

DeleteThis comment has been removed by the author.

ReplyDeleteSir would u plz tell me how 3 4 5 comes from

ReplyDelete