Please read Part - 1 and Part - 2 before reading this post.

Here W is the work. For e.g., if 5 men are cutting 10 trees in 2 days, working 4 hours per day. Then,

M = 5, D = 2, H = 4 and W = 10.

H1 = 6

D1 = 18

D2 = 12

H2 = ?

We know, H1 * D1 = H2 * D2

6 * 18 = H2 * 12

H2 = 9 hours

D1 = 20

H1 = 8

M2 = 20

D2 = 12

H2 = ?

We know, M1 * D1 * H1 = M2 * D2 * H2

15*20*8 = 20*12*H2

H2 = 10 hours

Number of taps required = 20*9/15 = 12

Let there be X number of men.

X men can finish a piece of work in 100 days. Hence total work = 100X

If there were (X - 10) men, it would have taken 110 days to finish the work. Total work in this case = 110(X - 10)

Total work remains the same. Hence,

100X = 110(X - 10)

X = 110

Efficiency of Subhash = 50/10 = 5 per hour

Efficiency of Subhash and Prakash = 300/40 = 7.5 per hour

Efficiency of Prakash = (Efficiency of Subhash and Prakash) - (Efficiency of Subhash) = 7.5 - 5 = 2.5

So Prakash can copy 2.5 pages per hour. To copy 30 pages, he would require 30/2.5 or 12 hours.

So total work = 200*200 units

200 workers have worked for 50 days. Hence they have finished 200*50 units of work.

Remaining work = 200*200 - 200*50 = 200*150

Let the number of additional workers required = X.

Now (200+X) workers will work for 100 days to finish the work as per the schedule.

Work they need to perform = (200 + X)*100

Now, (200 + X)*100 = 200*150

X = 100

120 workers finish 2/3 of the work in 64 days. So to complete the whole work, workers will take 64*3/2 or 96 days.

Total work to be performed = 120*96

Now the workers have already finished 2/3 of the work and only 1/3 work has to be performed.

Remaining work = 120*96/3 = 120*32

Let the contractor discharges X men. Remaining workers = 120-X. These workers will continue the work for (124-64) or 60 days. Hence,

120*32 = (120-X)*60

X = 56

M1 = 120, D1 = 64, W1 = 2/3

M2 = 120 – x, D2 = 60, W2 = 1/3

(M1*D1)/W1 = (M2*D2)/W2

120*64*3/2 = (120 - x)*60*3

x = 56

Here W is the work. For e.g., if 5 men are cutting 10 trees in 2 days, working 4 hours per day. Then,

M = 5, D = 2, H = 4 and W = 10.

H1 = 6

D1 = 18

D2 = 12

H2 = ?

We know, H1 * D1 = H2 * D2

6 * 18 = H2 * 12

H2 = 9 hours

**Answer : (B)**

**M1 = 15**

D1 = 20

H1 = 8

M2 = 20

D2 = 12

H2 = ?

We know, M1 * D1 * H1 = M2 * D2 * H2

15*20*8 = 20*12*H2

H2 = 10 hours

**Answer : (B)**

**In this question, Taps = Men**

Number of taps required = 20*9/15 = 12

**Answer : (B)**X men can finish a piece of work in 100 days. Hence total work = 100X

If there were (X - 10) men, it would have taken 110 days to finish the work. Total work in this case = 110(X - 10)

Total work remains the same. Hence,

100X = 110(X - 10)

X = 110

**Answer : (D)**Efficiency of Subhash = 50/10 = 5 per hour

Efficiency of Subhash and Prakash = 300/40 = 7.5 per hour

Efficiency of Prakash = (Efficiency of Subhash and Prakash) - (Efficiency of Subhash) = 7.5 - 5 = 2.5

So Prakash can copy 2.5 pages per hour. To copy 30 pages, he would require 30/2.5 or 12 hours.

**Answer : (D)**

40 men can finish a work in 60 days. Hence, total work = 40*60 = 2400

Let the 10 men left after X days.

For X days, all the 40 men worked. Total work performed = 40X

Now when 10 men quit, only 30 men were left to do the work and they took (70 - X) more days to finish it.

Total work done by 30 men = 30*(70 - X)

Now, 40X + 30*(70 - X) = 2400

X = 30 days

**Answer : (C)**

Let the total work = 360 units

Efficiency of A = 360/45 = 8 units

Efficiency of B = 360/40 = 9 units

Efficiency of A + B = 17 units

Let A left after X days.

For X days, both A and B worked. Hence work performed = 17X

B worked for 23 days. Hence work performed by B = 23*9 = 207 units

Now, 17X + 207 = 360

X = 9 days

**Answer : (D)**

B and C together do 8/23 of the work, hence A does (1 - 8/23) or 15/23 of the work.

A should be paid = 15*5290/23 = Rs. 3450

**Answer : (D)**

**Note :**In this question, they have asked the wages of A. Had they asked the wages of B, firstly you would have calculated the work performed by B with the formula-

Work done by B = (Portion of work done by A and B) + (Portion of work done by B and C) - 1

Work done by B = 19/23 + 8/23 - 1 = 4/23

Wages of B = 4*5290/23 = Rs. 920

**This is a very famous question. A company employed 200 workers to complete a certain work in 150 days. Here the total work is not 200*150 because 200 workers and 150 days was only a plan. In reality, only 1/4th of the work has been done in 50 days. So if they go with the same pace, 200 workers will take 200 days to complete the work.**

So total work = 200*200 units

200 workers have worked for 50 days. Hence they have finished 200*50 units of work.

Remaining work = 200*200 - 200*50 = 200*150

Let the number of additional workers required = X.

Now (200+X) workers will work for 100 days to finish the work as per the schedule.

Work they need to perform = (200 + X)*100

Now, (200 + X)*100 = 200*150

X = 100

**Answer : (C)**

**Q. 10) A contractor undertook to finish a certain work in 124 days and employed 120 men.After 64 days,he found that he had already done 2/3 of work. How many men can be discharged now so that the work may finish in time?****A) 56 B) 44 C) 50 D) 60**120 workers finish 2/3 of the work in 64 days. So to complete the whole work, workers will take 64*3/2 or 96 days.

Total work to be performed = 120*96

Now the workers have already finished 2/3 of the work and only 1/3 work has to be performed.

Remaining work = 120*96/3 = 120*32

Let the contractor discharges X men. Remaining workers = 120-X. These workers will continue the work for (124-64) or 60 days. Hence,

120*32 = (120-X)*60

X = 56

**Answer : (A)**

__Method 2__M2 = 120 – x, D2 = 60, W2 = 1/3

(M1*D1)/W1 = (M2*D2)/W2

120*64*3/2 = (120 - x)*60*3

x = 56

Let the second pipe fills the pool in X hours. Then first pipe takes (X+5) hours and the third pipe takes (X-4) hours to fill the pool. Now, 1st and 2nd pipe together take the same time to the fill the pool as the 3rd pipe alone. Hence,

1/(X+5) + 1/(X) = 1/(X - 4)

Solve this quadratic equation and you will get X = 10 hours

That means second pipe takes 10 hours to fill the pool while the third pipe takes 6 hours. Together they will take 10*6/(10 + 6) hours to fill the pool.

**Answer: (B)**

**I have covered almost all the possible questions from Time and Work that are asked by SSC. If you have any doubt in this topic, please drop a comment.**

**Keep Reading :)**

**To buy the super-hit SSC Hack-Book, follow the below link-**

sir is type k ques ko short me btaiye

ReplyDeleteTwo alloys A and B contain gold and silver in the ratio of 1 : 2 and 1 : 3 respectively. A third alloy C is formed by mixing A and B in the ratio of 2 : 3. Find the percentage of silver in the alloy C

Hello bhai apna con number dede mere se poora ratio ka chapter aata h with short trick meri Email id h

Deletesumitpal12595@gmail.com ispe bhej diye

Thanku sir...

ReplyDeletesir in reasoning i face problem in solving 1.missing number

ReplyDelete2. a_b_ _ c_a_

either it takes time to solve these two type problems or not able to solve at all. Plz tell the how to approach these type of questions . sometimes the missing letter series is too tough to make any pattern

A contractor undertook to finish a certain work in 124 days and employed 120 men.After 64 days,he found that he had already done 2/3 of work. How manu men can be discharged now so that the work may finish in time?

ReplyDeletePls solve

Q.9 ki tarah solve karo.

Delete2/3 work karne me 64 days lag rahe hain, that means pura work karne me 96 days lagenge.

Total work = 120*96

Rest is your home-work :P

it can also be done like the method you have explaine the first question..

DeleteThis comment has been removed by the author.

DeleteSir mere mock test me 110-115 bante hai....

ReplyDeleteResoning-40-43

Quant -40-45

Eng- 20-22

G s -10-20

Sir pls English k liye batao kuchh kyuki tier 2 me bhi English ka separate paper hoga 200 marks to main kaise English me score kr sakta hu????

Please help me @parshant sir

Its heartly humble request ....����

Bro somehow manage Tier-1, I will post english articles once Tier-1 is over.

DeleteIn the mean time you can read "Sentence Correction" chapter from SP Bakshi and on a daily basis you should memorize 15 words, idioms, one-word substitution and phrasal verbs.

Yaah.. I have Paramount English module.

DeleteIsn't it enough for tier 1??

Otherwise thank you so much

more than enough :)

DeleteI have just started cgl preparation 15 days ago , I've read only one third of Paramount book but confused in solving the questions ...therefore i couldn't score well in mock test....

DeleteThank you so much sir...Like this plz try to Complete other tropics as soon as possible sir because exam is too close...it be so much useful for our preparation ..Thanks alot for your kindness sir..

ReplyDeleteThis comment has been removed by the author.

ReplyDeletesin@+sin^2@+sin^3@=1 then cos^6@-4cos^4@+8cos^2@ is equal to question was asked in 8.07.2012 cgl ...sir please give a solution of it..by assuming value of @ is not working here ...if any trick will work on this question so please share a trick sir

ReplyDeletetake @= 270

Deleteanswer =0??

answer is 4

Deleteanswer is 4

DeleteThis comment has been removed by the author.

ReplyDeleteSir seriously you covered each and every topic.....and your way of teaching is also lucent....you are doing social work....keep writing for us.....thankyu so much sir

ReplyDeletewelcome :)

Deletesir according to newspaper report will ssc tier 1 qualifying and the exam will be onlineand the date will be postponded. sir is it true

ReplyDeletedon`t go by hindi newspaper ...they don`t have credibility

Deletea,b,c undertake to complete a piece of work for Rs 2574. A works for 8 days, b for 9 days and c for 12 days. If their daily wages are in the ratio of 3:4:5 what does c get?

ReplyDeletehey, i calculated the total work units which came out to be 72.

Deletetherefore efficiency came out to be A=9, B=8, C=6.

therefore the ratios should be 27:32:30.

i did not get how wages will be in the ratio of 24:45:48.

please explain. :(

No you cant calculate the efficiency because no where it is written that A "completes" the work in 8 days. A just works for 8 days.

DeleteLet the wages of A, B and C be 3x, 4x and 5x

A works for 8 days, hence total wages of A = 8*3x = 24x

B works for 9 days, hence total wages of B = 9*4x = 36x

C works for 12 days, hence total wages of C = 12*5x = 60x

Ratio of wages of A, B and C = 24x:36x:60x = 2:3:5

C gets = 5*2574/10 = Rs. 1287

Sorry in the previous reply I had written a wrong ratio.

Okay thanks a lot. I guess my book has wrong answer for this question too. The answer was 1056. But I got the solution.

DeleteA can complete a job in 12 days, b in 15 days. Both of them worked for 5 days and rest of work was finished by c. If total earning is Rs 720. Find wages of b.

ReplyDeletetotal work = 60 units

Deleteefficiency of B = 60/15 = 4

work done by B in 5 days= 5*4 =20

earning of B = 20/60 * 720

hey... got the correct answer...thanks :)

DeleteA b and c undertake to do a work For Rs 660 . A and b together do 5/8th of the work and remaining is done by c alone. How much should c get?

ReplyDeletework done by C = 3/8

Deletewage = 3/8*660

hey..really thanks for quick response but the answer is rs 180. a possibility answer is wrong?

DeleteYes... the answer is wrong. Rs. 180 should be the answer to this question -

DeleteA b and c undertake to do a work For Rs 660 . A and b together do 8/11 of the work and remaining is done by c alone. How much should c get?

okay. got it. thanks a ton!!

DeletesIR Exam ab postpone ho gya aap english class start kr do plz

ReplyDeletesir,kindly explain 6 th question,

ReplyDeletei am using MDH/W =constant(the same formula you have given above)

men days work

40 60 1 full unit

40 x x/60 units completed

30 (70-x) 59x/60 is remaining

now

(40* 60)/1 = (30(70-x))/(59x/60)

on solving this am not getting answer,its in fractions 210/239.

Kindly explain when i am doing wrong,please sir.

sir,kindly explain 6 th question,

ReplyDeletei am using MDH/W =constant(the same formula you have given above)

men days work

40 60 1 full unit

40 x x/60 units completed

30 (70-x) 59x/60 is remaining

now

(40* 60)/1 = (30(70-x))/(59x/60)

on solving this am not getting answer,its in fractions 210/239.

Kindly explain when i am doing wrong,please sir.

is there any other way to solve this ques? the calculation is time consuming.

ReplyDeleteJust use the formula M1*D1 = M2*D2

ReplyDelete40*60 = (40*x)+ (40-10)(70-x)

x is no.of days after which 10 men left the work.

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ReplyDelete