Saturday, 19 March 2016

[Q] Geometry Tricks - 1 [Important Formulae]

Many students asked me to share some geometry tricks. So here is the Part-1 :

(1) Be it algebra or geometry, such questions are always there that don't deserve your rough space.
Like the above questions asks you the value of x. Now value of x can't be negative in this context. Because CO = x - 3 and any negative value of 'x' will make CO negative, like if x = -8, then CO = -11. We know that side can never be negative. Hence all the options that have negative value for x are wrong.
Answer : (B)


In the above question a certain area is asked. Now see the options and observe that in options A, C and D if we take r=7, 2 and 1 respectively, then the area will become zero, and area can never be zero in this case, although value of 'r' can be 7, 2 or 1.
Answer : (B)
Note : Such questions are rare in geometry and in most of the questions you will have to pick up your pen, but still I shared these questions just to unleash the jugaad within you. Moreover, if you are able to solve even a single question with such approach, you will save at least 1 crucial minute in the examination hall.

(2) In geometry too, my beloved concept of 'symmetry' plays an important role. If in any question you find that some symmetrical expressions/equations are given, you can assume the triangle to be equilateral.
Q. 1 

In the above question you can assume that the triangle is equilateral. Then angles A, B and C will be 60. Hence sin2A + sin2B + sin2C = (√3/2)2 + (√3/2)2 + (√3/2)2 = 9/4
Answer : (B)
Note : If in any question, the sides of a triangle are given (like a, b and c), then you can assume a = b = c, but make sure any additional detail is not given. Like in the above question that I solved, some additional equations were given, but then too I supposed the triangle to be equilateral only because the equation was symmetrical. Had the equation been unsymmetrical, I could not have been able to assume a =b =c
Q. 2

Here the lengths of perpendiculars are given to be a, b and c. Note that no additional information is given, hence it is safe to assume a = b = c. Let the side of the triangle be 's'. The figure will look like this - 
We have to establish a relation between 'a' and 's'. In an equilateral triangle, the incentre, orthocentre, circumcentre and centroid, all coincide. So you can calculate 'a', by which ever method you like.
a = inradius = s/2√3 [The inradius of an equilateral triangle is s/2√3 and the circumradius is s/√3]
Hence s = 2√3a
We know the formula for calculating the area of an equilateral triangle = (√3/4)s2
= (√3/4) (2√3a)2
= 3√3a2

Now put a = b = c in all the options and check which one will give 3√3a2
A) √3a
B) 3√2a2
C) √2a
D) 3√3a2

Answer : (D)

Moving on...

I have found that SSC has some real love with 'Area of a triangle' and it keeps on asking it again and again under different contexts. Like in Tier 2 (2014) around 5 questions asked area of triangles.
Therefore it is very important that you memorize all the possible formulas to calculate it. This will save you a lot of time.
Note : All the below questions are taken from a single paper [Tier-2, 2014].

Formula 1 : (Applicable only for Right-Angled Triangle)

Q. 3

In the above question you may struggle to calculate the area. You can try this question yourself (with a timer), to see how much time you are taking...

There is a direct formula for such questions -

Apply this formula, area = (100^2 * sin30)/4 = 1250
Answer : (D)
Note : You can choose any of the angles of the triangle (except the 90 degree one) and you will get the same result. Like in the above question, the 3 angles of the triangle are 15, 75 and 90.
sin2*15 = sin30
sin2*75 = sin150
And we know that sin150 = sin30
Hence it doesn't matter which angle you take. But to avoid any confusion, always take the smaller angle (15 in this case).

Next question -


Q. 4

Again apply the same formula
Answer : (C)

Formula 2 :    ½*b*c*sinϴ

This formula is only applicable when ϴ lies between the sides 'b' and 'c'.



Q. 5

Apply the formula, area = 1/2 * 10 * 10 * sin45
Answer : (D)

Formula 3 : Area of a triangle = r * S
where r = inradius
S = semi-perimeter


Q. 6

Given, perimeter = 50, hence semi-perimeter = 25
Area = 6 * 25 = 150
Answer : (C)

Now when you know this formula, in Q. 2 above, where we had to establish relation between 's' and 'a', you can establish it by applying this formula too.
Area of an equilateral triangle = (√3/4)s2
Area of a triangle = inradius * semi-perimeter = a * (3s)/2
Now,
a * (3s)/2 = (√3/4)s2
or s = 2√3a    [Same result]

Geometry Part-2 to follow soon...

To buy the super-hit SSC Hack Book, follow the below link-
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32 comments:

  1. Sir marvellous..u have done a great thing for all of us.generally after qualifying no body helps in such a great way.thank u so much sir.
    I request u if u could give us all the important formulae for geometry yhen it would of much help.waiting for ur next post☺☺

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  2. This comment has been removed by the author.

    ReplyDelete
  3. Now my daily routine to refresh SSC hack blog to check updates. You are doing great sir. Thanks a lot

    ReplyDelete
  4. A sum of Rs.1550 was lent partly at 5% and partly at 8% simple interest. The total interest received after 3 years is Rs.300. The ratio of money lent at 5% to that at 8% is ?
    A)5:8
    B)8:5
    C)31:6
    D)16:15

    ReplyDelete
    Replies
    1. If an amount P1 is lent out at simple interest of R1% per annum and another amount P2 at simple interest rate of R2% per annum, then the rate of interest for the whole sum can be given by
      R = (P1.R1 + P2.R2)/(R1 + R2)
      SI=300, time=3 and P=1550
      calculate R from above data.
      Now apply the formula, you will get the answer 16:15

      Delete
  5. What annual installment will discharge a debt of Rs.6450 due in 4 years at 5 person simple interest?
    A) Rs. 1500
    B) Rs. 1400
    C) Rs. 1600
    D) Rs. 1550

    ReplyDelete
    Replies
    1. The annual instalment which will discharge a debt of D due in T years at R% simple interest per annum
      = 100D/[100T + RT(T-1)/2]
      D = 6450, T = 4, R = 5%
      Put the values
      Answer : 1500

      Delete
  6. Sir. If u have no problem,kindly send ur WhatsApp No.

    ReplyDelete
  7. This comment has been removed by the author.

    ReplyDelete
  8. Sin 20°sin40°sin60°sin80°

    Koi shortcut hah isko solv krne k sir ... pls rply

    ReplyDelete
    Replies
    1. Put the value of sin60
      now write sin40.sin80 = sin(60-20).sin(60+20)
      Apply the formula sin(a+b).sin(a-b) = sin^2a - sin^2b
      Hence sin40.sin80 = sin60^2 - sin20^2
      Then multiply and divide by 4
      Now apply the formula 3sinx - 4sin^3x = sin3x
      you will get the answer : 3/16

      Delete
  9. Abcd is a parallelogram . p is a point on BC such that pb:pc is 1:2. Do produced meets an produced at q. If the area of the triangle bpq is 20 sq units. What is the area of triangle dcp(

    ReplyDelete
  10. Abcd is a parallelogram . p is a point on BC such that pb:pc is 1:2. Do produced meets an produced at q. If the area of the triangle bpq is 20 sq units. What is the area of triangle dcp(

    ReplyDelete
    Replies
    1. There are typos in this question. Please post again...

      Delete
  11. Dear Prashanth , you are doing such a great service by helping all the aspirants out here. Please post such tricks for Algebra too when you get time . Wishing you to attain great heights and a happy life good health . Thanks a ton

    ReplyDelete
    Replies
    1. I have already shared algebra tricks-
      http://sschacks.blogspot.in/2016/03/algebra-tricks-for-ssc-cgl-algebra-is.html

      Delete
  12. Yaar apke marks kitne the? T1+T2+interview

    ReplyDelete
  13. Sorry, as I'm browsing through the mobile, I was unable to find it then . Got it. Thanks a ton :) thanks again for spending your quality time

    ReplyDelete
  14. teen admi A B C milkar ek kam krne par ek karya ko akele A se 6 hr kam me, akele B se 1 hr kam me aur C k akele kam krne k liye avshyak samay se adhe samya me pura kr skte h. A aur B milkar us karya ko kitne time me kr skte h??

    ReplyDelete
  15. if circumference of a circle is decreased by50% then the pecentage decrease in its area is????

    ReplyDelete
    Replies
    1. circumference is getting reduced by 50%, that means radius is getting reduced by 50%
      New area = pi * (0.5r)^2 = 0.25*pi*r^2
      From pi*r^2, the area has reduced to 0.25*pi*r^2
      So area has been reduced by 75%

      Delete
  16. Gr work prashant...every articles of urs is thougroly researched and is indeed a masterpiece...gr8 work

    ReplyDelete
  17. Q. chords AC and BD of a circle with centre O intersect at right angles at e. if angle OAB=25 degree then the value of angle EBC. sir please explain the concept of intersection of chords at right angle.

    ReplyDelete
  18. PALLAVI9918@GMAIL.COM
    PLZ SENT THE BOOKOF MNATH SIR

    ReplyDelete